Friday 6 September 2013

Class 6 - Binary to Decimal

 Number System
 
1. Binary Number System
Only 0 and 1 are allowed in binary number system. So the base is 2(only two numbers)
e.g:
 (101)2
2. Decimal Number System
0,1,2......9 are allowed in decimal number system. So the base is 10( 0 to 9,totally 10 numbers)
e.g:
(25)10

The base is written along with the number to identify the number system.
Conversion from binary to decimal :
20=1
21=2
22=4 (2 x 2)
23=8(2 x 2x 2)
24=16(2 x 2x 2 x 2)
 and so on.......



 
2. (110)2

1   1   0

 = 1 x 2 2 + 1 x 2 1+ 0 x 2

 = 4 + 2 + 0
= 6
Answer = (6) 10

3. (111)2
 = 1 x 2 2 + 1 x   2 1   + 1 x   2 0
= 4 + 2+ 1
= 7

4. (1011)2
=1 x   2 3  + 0 x 2 2 + 1 x   2 1   + 1 x   2 0

= 8+0 + 2+ 1
= 11

5. (1101)2
=1 x   2 3  + 1 x 2 2 + 0 x   2 1   + 1 x   2 0

= 8+4 + 0+ 1
= 13

Conversion from decimal to binary

This involves repeated division of the quotient by two, the remainder forms the part of the answer.
1. (4)10

4 / 2 = 2  remainder = 0
2/2 = 1    remainder = 0

You cannot divide 1 by 2, so stop now. Therefore the answer is
=(100)2

2. (7)10

7 / 2 = 3 remainder = 1
3 / 2 = 1 remainder = 1

= (111)2


3. (13)10

13 / 2 = 6 remainder = 1
6 / 2 = 3   remainder = 0
3 / 2 = 1   remainder = 1
= (1101)2

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